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Anthem
Joined: 14 Jul 2009
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 Posted: Fri Oct 09, 2009 7:25 am Post subject: |
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| It boggles the mind. Color me impressed. |
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Konglishman
Joined: 14 Sep 2007
Location: Nanjing
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| Posted: Fri Oct 09, 2009 7:29 am Post subject: |
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| Joe666 wrote: |
| Konglishman - You need a chick something fierce!!! Your gonna POP any day now!!! |
I keep finding myself backing out of relationships. I suppose that might have something to do with going through a divorce 2 and half years ago. Oh, well. Otherwise, things are going great for me. |
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The Cosmic Hum
Joined: 09 May 2003
Location: Sonic Space
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| Posted: Fri Oct 09, 2009 7:30 am Post subject: |
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Just for fun...as there are infinite answers to this ...speed is important...as are all the other factors when dealing with currents and water density...and sharks 
The answer is 700m.
A swims at the speed of light and meets B at B's island...which happens to be 700m from A's island.
A now goes for a beer and a nap.
A then jumps into the water and passes B at the said 400m from island B...no time for chatting as A has other plans in mind.
A enjoys the rest of his day drinking beer and scoring chicks.
B is eaten by sharks.
The rest is...as the say...history...not math.  |
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Konglishman
Joined: 14 Sep 2007
Location: Nanjing
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| Posted: Fri Oct 09, 2009 7:31 am Post subject: |
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| Panda wrote: |
Joe666
Its 10 times fun than scoring any chicks.......
Konglishman rocks.....................(I was like......wow) |
Well, I am the man.  |
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Panda
Joined: 25 Oct 2008
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| Posted: Fri Oct 09, 2009 9:05 pm Post subject: |
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Joe666
Joined: 19 Nov 2008
Location: Jesus it's hot down here!
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| Posted: Fri Oct 09, 2009 9:30 pm Post subject: |
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| Panda and the Konglishman = A match made in ................ Korea? You two should get together and talk this out!! Panda, just be gentle on the man!! |
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movybuf
Joined: 01 Jan 2007
Location: Mokdong
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| Posted: Fri Oct 09, 2009 9:43 pm Post subject: |
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| I still add numbers using my fingers. |
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midgic
Joined: 14 Feb 2004
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| Posted: Fri Oct 09, 2009 10:22 pm Post subject: |
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ABCDEF X C = CDEFAB
142857 X 2 = 285714 |
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midgic
Joined: 14 Feb 2004
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| Posted: Fri Oct 09, 2009 10:28 pm Post subject: |
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A, B, C, D, and E are on side 1. They want to cross to side 2.
steps (minutes)
1. A and B cross to side 2 (3 minutes)
2. A returns to side 1 (1)
3. D and E cross to side 2 (12)
4. B returns to side 1 (3)
5. A and C cross to side 2 (6)
6. A returns to side 1 (1)
7. A and B cross to side 2 (3)
Now everyone is on side 2. It took a total of 29 minutes. |
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Panda
Joined: 25 Oct 2008
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| Posted: Fri Oct 09, 2009 10:34 pm Post subject: |
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Joe666: This is what nerdies do when they get bored~! Stop laughing 
Midgic: Neat~! |
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Joe666
Joined: 19 Nov 2008
Location: Jesus it's hot down here!
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| Posted: Fri Oct 09, 2009 10:46 pm Post subject: |
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Panda wrote:
| Quote: |
Joe666: This is what nerdies do when they get bored~! Stop laughing
Midgic: Neat~! |
I'm not laughing, I'm actually touched. You two crazies should get together. Imagine the offspring, craniums the size of beach balls. |
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seonsengnimble
Joined: 02 Jun 2009
Location: taking a ride on the magic English bus
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| Posted: Sat Oct 10, 2009 2:13 am Post subject: |
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I got it in about 20 minutes. I didn't use any of your fancy equations, though. I just guessed and checked and narrowed in on 1700.
Here was my slow method:
The person swimming from a to b was going slower than the person going from b to a since going to a and back to the first meeting point (C) plus the distance from C to 400 has to be more than going from C to b and then 400. If the person swimming from a to b was going faster, it wouldn't make sense for it to take him more time to go from c to b then 400(d) than it would for the slower person to go from C to A to d.
I then set up some ratios for guessed distances between B and C. I started with 800. 700/800 = 1200/1800, nope. Second ratio is smaller. I did this for a while until I got 700/1000 or 7/10= 14/20 and found the distance from C to B. |
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ontheway
Joined: 24 Aug 2005
Location: Somewhere under the rainbow...
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| Posted: Sat Oct 10, 2009 4:57 am Post subject: |
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| seonsengnimble wrote: |
I got it in about 20 minutes. I didn't use any of your fancy equations, though. I just guessed and checked and narrowed in on 1700.
Here was my slow method:
The person swimming from a to b was going slower than the person going from b to a since going to a and back to the first meeting point (C) plus the distance from C to 400 has to be more than going from C to b and then 400. If the person swimming from a to b was going faster, it wouldn't make sense for it to take him more time to go from c to b then 400(d) than it would for the slower person to go from C to A to d.
I then set up some ratios for guessed distances between B and C. I started with 800. 700/800 = 1200/1800, nope. Second ratio is smaller. I did this for a while until I got 700/1000 or 7/10= 14/20 and found the distance from C to B. |
You used reasoning and a process called iteration. Fine methodology.
The others used simple algebra, but there's no need to include time, just distance and proportion.
There are required assumptions missing, however. You must assume that the swimmers swim non-stop at a constant speed. This should be in the setup or the problem has no solution. |
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ontheway
Joined: 24 Aug 2005
Location: Somewhere under the rainbow...
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| Posted: Sat Oct 10, 2009 5:01 am Post subject: |
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| midgic wrote: |
A, B, C, D, and E are on side 1. They want to cross to side 2.
steps (minutes)
1. A and B cross to side 2 (3 minutes)
2. A returns to side 1 (1)
3. D and E cross to side 2 (12)
4. B returns to side 1 (3)
5. A and C cross to side 2 (6)
6. A returns to side 1 (1)
7. A and B cross to side 2 (3)
Now everyone is on side 2. It took a total of 29 minutes. |
What? Where is the problem set up? No info.
With no info, the best answer is:
| Quote: |
A, B, C, D, and E are on side 1. They want to cross to side 2.
steps (minutes)
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answer:
A, B, C, D, and E all go to side two.
One step. One minute.
What was the actual problem? |
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ontheway
Joined: 24 Aug 2005
Location: Somewhere under the rainbow...
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| Posted: Sat Oct 10, 2009 5:21 am Post subject: |
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| midgic wrote: |
ABCDEF X C = CDEFAB
142857 X 2 = 285714 |
142857 X 2 = 285714 true
ABCDEF X C = CDEFAB sometimes, but usually not true
123456 x 3 = 370368 for example.
Are you asking us to define the paramaters of your solutions? |
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