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logic problems
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tomato



Joined: 31 Jan 2003
Location: I get so little foreign language experience, I must be in Koreatown, Los Angeles.

PostPosted: Tue Apr 04, 2006 7:04 am    Post subject: Reply with quote

I can't think about that right now. If I do, I'll go crazy. I'll think about that tomorrow.

Meanwhile, I'm burning to share another new one:
Yes, I know, I'm violating the rule which I set in the OP:

Gorgeous George, King Kong, and Pistol Pete got in a flame war.
Between the three of them, each member called another member an "apologist," a "loser," and a "whiner."
Each member delivered one insult, and each member received one insult.

Here are the clues:

1. Since no member had the humility to insult himself, you can mark a diagonal row of X's on one of the charts.
2. GG did not say "apologist," PP did not say "loser," and KK did not say "whiner."
3. KK got called an "apologist."

See if you can match the subjects, objects, and epithets.
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robot



Joined: 07 Mar 2006

PostPosted: Tue Apr 04, 2006 8:19 am    Post subject: when in rome... Reply with quote

yo

back with another shot at it. the clue about using both sides helped.

with this sequence you can come to any number through addition or subtraction:

1, 3, 9, 27, 81, 243, 729, 2187...

for example:

9 = 9
99 = 81 + 27 - 9
999 = 729 + 243 + 27
1400 = 2187 - 729 - 81 + 27 - 3 - 1

that's 8 weights needed total. far better than roman numerals.

ROBT.
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midgic



Joined: 14 Feb 2004

PostPosted: Tue Apr 04, 2006 8:24 pm    Post subject: Reply with quote

robot, that's a great solution.
However, I think it's possible to use fewer weights and still be able to determine how many 1-gram weights are in the bag.

Tomato's puzzle:
KingKong called George a loser.
George called Pete a whiner.
Pete called KingKong an apologist.
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tomato



Joined: 31 Jan 2003
Location: I get so little foreign language experience, I must be in Koreatown, Los Angeles.

PostPosted: Tue Apr 04, 2006 8:45 pm    Post subject: Reply with quote

Migdic, you got mine.
Now if I could ever get yours!
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robot



Joined: 07 Mar 2006

PostPosted: Tue Apr 04, 2006 9:41 pm    Post subject: Reply with quote

i give up. Confused

i'ma go outside & play some hockey.

ROBT.
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tomato



Joined: 31 Jan 2003
Location: I get so little foreign language experience, I must be in Koreatown, Los Angeles.

PostPosted: Wed Apr 05, 2006 3:58 am    Post subject: Reply with quote

midgic wrote:
Hint available upon request....


I'm afraid I'll have to take you up on that.
I'm sure it's a formula which is so simple that I will hate myself, but
give it to me anyway.

Huck was thinking along the factorial route for a while.
It doesn't have to do with factorials, does it?
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midgic



Joined: 14 Feb 2004

PostPosted: Wed Apr 05, 2006 5:21 am    Post subject: Reply with quote

Hi Tomato,

The hint at this point is to check out robot's solution.
An improvement on that solution requires just one more logical step.

To simplify things: instead of up to 1400, think about it for up to 6 gram-weights. Can you figure out a way to verify how many gram-weights are in the bag, given that there are either 1, 2, 3, 4, 5, or 6 weights in the bag? Can you do it using only two weights?
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Nowhere Man



Joined: 08 Feb 2004

PostPosted: Wed Apr 05, 2006 6:14 am    Post subject: ... Reply with quote

Sorry if it's been done, but...

http://www.albinoblacksheep.com/flash/mind.php

Exclamation Question Idea Razz Laughing Embarassed
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midgic



Joined: 14 Feb 2004

PostPosted: Wed Apr 05, 2006 6:53 am    Post subject: Reply with quote

Nowhere Man's question:

A two-digit number has the form 10x + y.
Adding the two digits gives x+y.
The two-digit number minus the sum of the digits gives:
(10x + y) - (x + y) = 9x
The answer is always a multiple of 9, and since x is between 1 and 9,
the answer is one of: 9, 18, 27, 36, 45, 54, 63, 72,or 81.
If you look at the chart, those numbers all have the same symbol next to them.
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tomato



Joined: 31 Jan 2003
Location: I get so little foreign language experience, I must be in Koreatown, Los Angeles.

PostPosted: Wed Apr 05, 2006 9:02 am    Post subject: Reply with quote

Sorry, Migdic, but I can only narrow it down to three weights:



My chart purports to show all the possible combinations of two numbers between 1 and 6.

Each entry in the column marked NUMBERS ACCOUNTED FOR purports to account for all the numbers which could be weighed using those two weights.
That incluses the weights added together, the lighter weight subtracted from the heavier weight, and the weights themselves.

I was unable to get all 6 numbers on a single row.

However, I can find combinations in which three weights will do the job.
Such combinations are:

1-2-3, 1-2-4, 1-2-5, 1-3-5, 1-3-6, 1-4-6, and 2-3-4.

I am assuming that I cannot have any two weights of the same value.
Am I right?
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midgic



Joined: 14 Feb 2004

PostPosted: Wed Apr 05, 2006 7:49 pm    Post subject: Reply with quote

Hi Tomato,

Your table of combinations with 2 weights shows 6 different solutions which solve the problem. This is where the other logical step comes in.
Hint: The scale doesn't necessarily have to balance in order to figure out the number of weights in the bag.
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huck



Joined: 19 Jan 2003

PostPosted: Wed Apr 05, 2006 7:56 pm    Post subject: Reply with quote

For the weighty problem....

You need.. 1, 3, 5, 10, 20, 40, 80, 160, 320, 640, and ??? 700?

that's 11 weights...

is it possible to do it with less? (I just saw Robot's and worked on it...his would work, so that beats mine)

For the 1-6 gram question midgic asked tomato..

you would need 2 and 4 grams....if, for example, you put the 2 gram weight on there, and it wasn't enough, and then you put the 4 gram weight on there and it was too much, then you would know that it weighs 3 grams.
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midgic



Joined: 14 Feb 2004

PostPosted: Wed Apr 05, 2006 10:13 pm    Post subject: Reply with quote

Quote:

you would need 2 and 4 grams....if, for example, you put the 2 gram weight on there, and it wasn't enough, and then you put the 4 gram weight on there and it was too much, then you would know that it weighs 3 grams.


That's the logical step required to bring the number of weights down to a smaller number.

There's a fairly simple formula or pattern which will give the smallest number of weights for larger numbers.

Hint: The first weight is 2.
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nautilus



Joined: 26 Nov 2005
Location: Je jump, Tu jump, oui jump!

PostPosted: Thu Apr 06, 2006 1:10 am    Post subject: Reply with quote

Talhing of logic problems, heres one. Why do Koreans always leave everything to the last possible moment?
I understand their thinking as regards wedding arrangements- it is considered presumptuous to make wedding plans too far ahead, and it is seen as boastful/ostentatious to send out invitations announcing your matrimony early on- these things wait until a few days before the ceremony.

However, I'm stumped as to why in business and the workplace, the lack of prior arrangements/planning persist?You could tell them that war will break out on a given day and time, a year ahead. That entire year they would not make any precautions or preparation. Then about 1 minute before bombs started dropping, they would all cram together in sheer chaos and pandemonium looking for the non existent shelters that nobody had bothered to build.

Insane!! Shocked
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